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Calculate difference in specific heats f...

Calculate difference in specific heats for `1` gram of air at `N.T.P`. Given density of air at N.T.P. is `1.293 g litre^(-1), j=4.2xx10^(7)" erg "cal^(-1)`.

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The correct Answer is:
`0.068 cal g^(-1)K^(-1)`
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Calculate the r.m.s. velocity of air molecules at S.T.P. Given density of air at S.T.P. is 1.296 kg m^(-3) .

Calculate the value of c_(v) for air, given that c_(p) = 0.23 calorie g^(-1)K^(-1) . Density of the air at S.T.P. is 1.293 g litre ^(-1) and J = 4.2 xx 10^(7) erg calorie ^(-1) .

Calculate the two specific heats of nitrogen from the following data : gamma = c_(p)//c_(v) = 1.51 density of nitrogen at N.T.P = 1.234 g litre ^(-1) and J = 4.2 xx 10^(7) erg cal^(-1) .

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