1g of water at `100^(@)C` is converted into steam at the same temperature. If the volume of steam is 1671 `cm^(3)`, find the change in the internal energy of the system. Latent of steam `=2256 Jg^(-1)`. Given 1 atmospheric pressure =`1.013xx10^(5) Nm^(-2)`

When 1 g of water at 100^@ C gets converted into steam at the same temperature, the change in volume is approximately

One kg of water at 373K is converted into steam at the same temperature. The volume 1 cm^(3) of water becomes 1671 cm^(3) on boiling. Calculate the change in internal energy of the system , if heat of vaporisation is 540 cal g^(-1) . Given standard atmospheric pressure =1.013xx10^(5) Nm^(-2) .

1.0 m^(3) of water is converted into 1671 m^(3) of steam at atmospheric pressure and 100^(@)C temperature. The latent heat of vaporisation of water is 2.3xx10^(6) J kg^(-1) . If 2.0 kg of water be converted into steam at atmospheric pressure and 100^(@)C temperature, then how much will be the increases in its internal energy? Density of water 1.0xx10^(3) kg m^(-3) , atmospheric pressure = 1.01xx10^(5) Nm^(-2) .

2g ice at 0^(@)C is mixed with 1 g steam at 100^(@)C . Find the final temperature of the mixture.

1 gm of ice at 0^@C is converted to steam at 100^@C the amount of heat required will be (L_("steam") = 536 cal//g) .

A sample of 0.5 g water at 100°C and 1 atm pressure requires 270 cal heat energy to convert to steam at 100°C. If at the same pressure, volume of the steam produced is 835.5 cc then change in internal energy of the sample is (1 cal = 4.2 J, 1 atm 10^5 N/m^2 )

calculate the increase in internal energy of 1 kg of water at 100(0)C when it is converted into steam at the same temperature and at 1atm (100 kPa). The density of water and steam are 1000 kg m^(-3) and 0.6 kg m^(-3) respectively. The latent heat of vaporization of water =2.25xx10^(6) J kg^(1) .