At `0^(@)C` and normal atmospheric pressure, the volume of 1 gram of water increases from `1 c.c "to" 1.091 c.c` on freezing. What will be the change in its internal energy? Normal atmospheric pressure is `1.013xx10^(5)N//m^(2)` and latent heat of melting of ice `= 80 cal//gram`.

At 1 atmospheric pressure, 1000 g of water having a volume of 1000 cm^3 becomes 1.097 cm^3 of ice on freezing. The heat of fusion of water at 1 atmosphere is 80.0 cal//g . What is the change in internal energy during the process?

The boiling point of pure water is ________ .^(@)C , at normal atmospheric pressure.

1g of water at 100^(@)C is converted into steam at the same temperature. If the volume of steam is 1671 cm^(3) , find the change in the internal energy of the system. Latent of steam =2256 Jg^(-1) . Given 1 atmospheric pressure = 1.013xx10^(5) Nm^(-2)

A 1.0 kg bar of copper is heated at atmospheric pressure (1.01xx10^5N//m^2) . If its temperature increases from 20^@C to 20^@C , calculate the change in its internal energy. alpha=7.0xx10^-6//^@C , rho=8.92xx10^3kg//m^3 and c=387J//kg-^@C .

100 gm of water at 20^@C is converted into ice at 0^@C by a refrigerator in 2 hours. What will be the quantity of heat removed per minute? Specific heat of water = 1 cal g^(-1) C^(-1) and latent heat of ice = 80 cal g^(-1)

1.0 m^(3) of water is converted into 1671 m^(3) of steam at atmospheric pressure and 100^(@)C temperature. The latent heat of vaporisation of water is 2.3xx10^(6) J kg^(-1) . If 2.0 kg of water be converted into steam at atmospheric pressure and 100^(@)C temperature, then how much will be the increases in its internal energy? Density of water 1.0xx10^(3) kg m^(-3) , atmospheric pressure = 1.01xx10^(5) Nm^(-2) .

At normal pressure and 0^(@)C temperature the volume of 1 kg of ice is reduced by 91 cm^(3) on melting . Laters heat of melting of ice is 3.4xx 10^(5)J//kg . Calculate the changes in the internal energy when 2 kg of ice melts normal pressure and 0^(@)C. (P=1.01 xx 10^(5) Nm^(-2))