A thermocole cubical icebox of side 30 cm has a thickness of 5.0 cm if 4.0 kg of ice are put ini the box, estimate the amount of ice remaining after 6 h. The outside temperature is `45^@C` and coefficient of thermal conductivity of thermocole`=0.01 J//kg`.

A cubical ice box of side 50 cm has a thickness of 5.0 cm. if 5 kg of ice is put in the box, estimate the amount of ice remaining after 4 hours. The outside temperature is 40^(@)C and coefficient of thermal conductivity of the material of the box = 0.01 Js^(-1) m^(-1) .^(@)C^(-1) . Heat of fusion of ice = 335 Jg^(-1) .

A cubical thermocol ice box of side length 30cm has thichess of 5.0cm If 4.0kg of ice is put in the box estimate the amount of ice remaining after 6hr The utside temperature is 45^(@)C and co-efficinet of the thermal conductivity of the thermocol is 0.01 J s^(-1) m^(-1) K^(1) (Latent Heat of fusion of water =335 xx 10^(3) Jkg^(-1)) .

Estimate the rate at which ice would melt in a wooden box 2.5 mm thick and of inside measurement 100 cm x 60 cm x 40 cm, assumming that external temperature is 32 .^(@)C and coefficient of thermal conductivity of wood is 0.168 Wm^(-1) K^(-1) . Given L=80 cal//g .

A cubical icebox made of thermocol of thickness 4 cm has each side equal to 20 cm. An ice block of mass 500 g is placed inside the box. If the box is suspended in a room at 50^@C , what will be the approximate mass of unmelted ice left in 2 hours? Take, coefficient of thermal conductivity of thermocol = 10^(-2) Wm^(-1) K^(-1) Latent heat of fusion of water = 3.35 xx 10^5 J kg^(-1)

A ice box of styrofoam (thermal conductivity = 0.01 J ms^(-1)K^(-1) ) is used to keep liquid cool. It has a total wall area, including lid, of 10.8 m^(2) and wall thickness of 2.0 cm. A bottle of water is placed in the box and filled with ice. If the outside temperature is 30^(@)C , the rate of flow of heat into the box is (in J//s)

Estimate the rate at which ice would melt in a wooden box 20 mm thick and of inside measurement 200 cm x 100 cm x 100 cm assumming that external temperature is 27^(@)C and coefficient of thermal conductivity of wood is 0.0004 cal s^(-1) cm^(-1) .^(@)C^(-1) .

‘cold box’ in the shape of a cube of edge 50 cm is made of ‘thermocol’ material 4.0 cm thick. If the outside temperature is 30^(@)C the quantity of ice that will melt each hour inside the ‘cold box’ is : (the thermal conductivity of the thermocol material is 0.050 W//mK)

For a glass window of area 1500 cm^2 and thickness 0.5 cm, determine the rate of loss of heat if the temperature inside the window is 35^@C and outside is -2^@C . Take, coefficient of thermal conductivity of glass = 2.2 xx 10^(-3) cal s^(-1) cm^(-1) K^(-1)

An ice box used for keeping eatables cool has a total wall area of 1m^2 and a wall thichness of 5.0 cm. The thermal cunductivity of the ice box is K=0.01 J//m^@C . It is filled with large amount of ice at 0^@C along with eatables on a dfay when the temperature is 30^@C The latent heat of fusion of ice is 334xx10^3 J//kg . The amount of ice melted in one day is ( 1 day =86,000s )