A black body at `27^(@)C` surrounds another black body at `-73^(@)C`. Calculate the net heat transfer per second per square meter of the body at higher temperature..

The energy emitted per second by a black body at 1227^(@)C is E. If the temperature of the black body is increased to 2727^(@)C the energy emitted per second in the terms of E in the second case.

One black body at temperature T is surrounded by another black body at temperate T_1(T_1ltT) . At T, the radiation emitted by inner blackbody per unit area per second is proportional to

A black body of 127^(@)C radiates heat at the rate of 5cal//cm^(2) -second. At 527^(@)C , the rate of heat radiated in the same units will be

The rate of emission of radiation of a black body at 273^(@)C is E , then the rate of emission of raidiation of this body at 0^(@)C will be

A black body is at a temperature of 527^(@)C , to radiate twice as much energy per second its temperature must be increased to

Calculate the temperature of the black body from given graph.

A black body initially at 27^(@)C is heated to 327^(@)C is heated to 327^(@)C . How many times is total heat emitted at the higher temperature than emitted at lower temperature ? What is the wavelength of the maximum energy radiation at the higher temperature ? Wien's constant = 2.898 xx 10^(-3) mK .