A liquid takes 5 minutes to cool from `80^@C` to` 50^@C` . How much time will it take to cool from `60^@C` to `30^@C`? The temperature of surroundings is `20^@C`.

A body cools from 80^(@)C to 50^(@)C in 5 min-utes Calculate the time it takes to cool from 60^(@)C to 30^(@)C The temperature of the surroundings is 20^(@)C .

A body cools from 90^@C to 80^@C in 2 minutes. How long will it take to cool from 70^@C to 50^@C if temperature of surroundings is 16^@C ?

A hot liquid takes 10 minute to cool from 70^(@)C to 60^(@)C . The time taken by the liquid to cool from 60^(@)C to 50^(@)C is

If a body takes 6 minutes to cool from 80°C to 70°C, how long will it take to cool from 60°C to 50°C, if the surrounding temperature is 25°C?

A hot body obeying Newton's law of cooling is cooling down from its peak value 80^@C to an ambient temperature of 30^@C . It takes 5 minutes in cooling down from 80^@C to 40^@C . How much time will it take to cool down from 62^@C to 32^@C ? (Given In 2 = 0.693, In 5 = 1.609)

A body cools from 50^@C to 49^@C in 5 s. How long will it take to cool from 40^@C to 39.5^@C ? Assume the temperature of surroundings to be 30^@C and Newton's law of cooling to be valid:

A body cools from 50.0^(@)C to 48^(@)C in 5s. How long will it take to cool from 40.0^(@)C to 39^(@)C ? Assume the temperature of surroundings to be 30.0^(@)C and Newton's law of cooling to be valid.