Find the fundamental note emitted by a string of length `10sqrt(10)` cm under tension of 3.14 kg. Radius of string is 0.55 mm and density `=9.8gcm^(-3)`.

What will be the fundamental note emitted by a string of length 20 sqrt(10) cm under a tension of 6.28 kg st if its radius and density are 0.2 mm and 19.6 g//cm^(3) , respectively ?

the frequency of a note emitted by a silver wire of length 25 cm is 256 when the tension is 10 kg.Calculate the radius of the wire (Density of silver =10.5xx10^(3)kgm^(-3) )

In order to double the frequency of the fundamental note emitted by a stretched string, the length is reduced to (3)/(4) th of the original length and the tension is changed. The factor by which the tension is to be changed is

Calculate the fundamental frequency of a sonometer wire fo length 20cm, tension 25N, cross sectional area 10^(-2)cm^(2) and density of material =10^(4)kg//m^(3) .

The frequency of the note emitted by a silver wire 1 mm in diameter and 50 cm in length is 256 Hz.Find the tension in the wire, if density of silver is 10.5 g cm^(-3) .

A sphere of radius 25 cm and mass 1 kg is hung by a string of negligible mass and length 40 cm, then tension in the string is -

Two identical charged spheres are suspended by strings of equal lengths. The strings make an angle of 30^@ with each other. When suspended in a liquid of density 0.8gcm^-3 , the angle remains the same. If density of the material of the sphere is 1.6gcm^-3 , the dielectric constant of the liquid is

A string of mass per unit length mu is clamped at both ends such that one end of the string is at x = 0 and the other is at x =l . When string vibrates in fundamental mode, amplitude of the midpoint O of the string is a, tension in a, tension in the string is T and amplitude of vibration is A. Find the total oscillation energy stored in the string.