The first overtone of an open orgen pipe beats with the first ouertone of a closed orgen pipe with a beat frequency of `2.2 H_(Z)` . The fundamental frequency of the closed organ pipe is `110 H_(Z)` . Find the lengths of the pipes . Speed of sound in air `u = 330 m//s` .

The first obertone of an open organ pipe beats with the first overtone of a closed organ pipe with a beat frequency of 2.2 Hz. The fudamental frequency of clos3ed organ pipe is 110 Hz. Find length of the open pipe. (Given, sound in air =330 m/s )

The second overtone of an open pipe beats with the seconds overtone of a closed pipe with a beat frequency of 3.2 Hz. If the fundamental frequency of closed organ pipe is 120 Hz, calculate the lengths of the pipes. Take, Velocity of sound in air = 320 m/s

The first overtone of an open organ pipe(of length L_(0) ) beats with the first overtone of a closed organ pipe(of length L_(c) ) with a beat frequency of 10Hz.The fundamental frequency of the closed pipe is 110Hz .If the speed of sound is 330ms then fundamental frequency of open pipe is ?

The first overtone in a closed pipe has a frequency

the fundamental frequency of a closed organ pipe is 50 Hz . The frequency of the second overtone is

The first overtone of an open pipe has frequency n.The first overtone of a closed pipe of the same length will have frequently

The second overtone of an open organ pipe beats with the third overtone of the closed organ pipe. The beat frequency is 3.3 Hz. What will be the length of pipes if fundamental frequency of closed organ pipe is 120 Hz ? Velocity of sound = 340 m/s

Find the fundamental frequency of a closed pipe, if the length of the air column is 42 m . (speed of sound in air = 332 m/sec )

The first overtone frequency of a closed organ pipe P_1 is equal to the fundamental frequency of an open organ pipe P_2 . If the length of the pipe P_1 is 30 cm, what will be the length of P_2 ?