A particle executes simple harmonic motion between `x = -A and x = + A`. The time taken for it to go from `0 to A//2 is T_1 and to go from A//2 to (A) is (T_2)`. Then.

A particle undergoes simple harmonic motion having time period T. The time taken in 3/8th oscillation is

The phase of a particle executing simple harmonic motion is pi/2 when it has

A particle executes a simple harmonic motion of time period T. Find the time taken by the particle to go directly from its mean position to half the amplitude.

A simple harmonic motion has an amplitude A and time period T. What is the time taken to travel from x=A to x=A//2 ?

The periodic time of a particle doing simple harmonic motion is 4 second . The time taken by it to go from its mean position to half the maximum displacement (amplitude) is

A particle executing simple harmonic motion with time period T. the time period with which its kinetic energy oscilltes is

A pariticle is performing SHM of amplitude "A" and time period "T" . Find the time taken by the period to go from 0 to A//2 .

For a particle executing simple harmonic motion, the amplitude is A and time period is T. The maximum speed will be

A particle executes SHM of amplitude A. If T_1 and T_2 are the times taken by the particle to traverse from 0 to A/2 and from A/2 to A respectively, then T_1/T_2 will be equal to