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sin20^@(4+sec20^@)=...

`sin20^@(4+sec20^@)=`

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`sin20^@(4+sec20^@)`
`=sin20^@(4+1/cos20^@)`
`=(4sin20^@cos20^@+sin20^@)/(cos20^@)`
`=(2sin40^@+sin20^@)/(cos20^@)`
`=(2sin(60-20)^@+sin20^@)/(cos20^@)`
`=(2sin60^@cos20^@-2cos60^@sin20^@+sin20^@)/(cos20^@)`
`=(2(sqrt3/2)cos20^@-2(1/2)sin20^@+sin20^@)/(cos20^@)`
`=(sqrt3cos20^@-sin20^@+sin20^@)/(cos20^@)`
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