y=ae^(3x)+be^(-2x)

The differential equation for y=ae^(x)+be^(-2x) is

Verify that y=ae^(3x)+be^(-x) is a solution of differential equation (d^2y)/(dx^2)-2(dy)/(dx)-3y=0

Verify that y=ae^(3x)+be^(-x) is a solution of differential equation (d^2y)/(dx^2)-2(dy)/(dx)-3y=0

If y=ae^(2x)+be^(-2x) then which of the following is true ?

The differential equation obtained by eliminating a and b from y=ae^(3x)+be^(-3x) is

y=ae^(2x)+be^(-3x) , a and b being arbitrary constants.

The differential equation satisfying all the curves y=ae^(2x)+be^(-3x), where a and b are arbitrary constants,is

Find differential equation of the curve y=ae^(3x)+be^(5x) .