If ` A=[ [0,-tan((alpha)/2)],[tan(alpha/2),0]] then (I-A)[[cosalpha,-sinalpha],[sinalpha,cosalpha]]` =

If A=[[0,-tan(alpha/2)],[tan(alpha/2),0]] show that (I+A) = (I-A)[[cosalpha,-sinalpha],[sinalpha,cosalpha]] where I=[[1,0],[0,1]]

If A=[(cas alpha, sinalpha),(-sinalpha,cosalpha)], AA'=

If A_(alpha)=[(cosalpha,-sinalpha),(sinalpha,cosalpha)] , then

If A= [[cosalpha,sinalpha],[-sinalpha,cosalpha]] then show that A^2=[[cos2alpha,sin2alpha],[-sin2alpha,cos2alpha]]

If A=[[cosalpha,sinalpha],[-sinalpha,cosalpha]] ,show that A^2=[[cos2alpha,sin2alpha],[-sin2alpha,cos2alpha]]

Select the correct option from the given alternatives.If A = [[cosalpha,sinalpha],[-sinalpha,cosalpha]] then A^-1 = ? 1) [[frac{1}{cosalpha},-frac{1}{sinalpha],[frac{1}{sinalpha},frac{1}{cosalpha]] 2) [[cosalpha,-sinalpha],[sinalpha,cosalpha]] 3) [[-cosalpha,sinalpha],[-sinalpha,cosalpha]] 4) [[-cosalpha,sinalpha],[sinalpha,-cosalpha]]

Prove that (1-cosalpha)/sinalpha=tan(alpha/2)

If A_(alpha)=[(cosalpha,sinalpha),(-sinalpha,cosalpha)] then (A_(alpha))^2=?

IF (cosalpha)/a=(sinalpha)/b then a cos 2alpha+bsin 2 alpha =……….

For a real number alpha , let A(alpha) denote the matrix ((cosalpha,sinalpha),(-sinalpha,cosalpha)) . Then for real numbers alpha_(1) and alpha_(2) , the value of A(alpha_(1))A(alpha_(2)) is -