In Fig. 4.123, ABCD is a trapezium with `AB || DC`. If `Delta AED` is similar to `Delta BEC`, prove that `AD= BC`.

In Fig.4.116,ABCD is a trapezium with ABDC.If AED is similar to BEC, prove that AD=BC.( FIGURE )

In the trapezium ABCD, AB || DC and Delta ARD - Delta BEC . Then Prove that AD = BC.

ABCD is a trapezium in which AB||DC the diagonals AC and BD are intersecting at E. IF DeltaAED is similar to DeltaBEC , then prove that AD=BC.

ABCD is trapezium with AB || DC. The diagonal AC and BD intersect at E . If Delta AED ~ Delta BEC . Prove that AD = BC .

In the given figure ABCD is a trapezium with AB || DC. E and F are respectively midpoint of AD and BC. Prove that, EF=1/(2)(AB+CD)

In the given figure ABCD is a trapezium with AB || Dc and AD = BC prove that DeltaABC~~DeltaBAD

ABCD is a trapezium with AB||DC. A line parallel to AC intersects AB at X and BC at Y. Prove that ar( Delta ADX) = ar( Delta ACY).

In the given figure ABCD is a trapezium with AB || Dc and AD = BC prove that angleA=angleB

In the given figure ABCD is a trapezium with AB || Dc and AD = BC prove that diagonal AC = diagonal BD