for the set of equation `x-y+3z=2,2x-y+z=4 and x-2y+alphaz=3` which of the following is incorrect? (i) No solution for `alpha=0`(ii) unique solution for `alpha!=0`(iii) infinite solution for `alpha=0`(iv) unique solution for `alpha=0`

The system of equations -2x+y+z=a , x-2y+z=b , x+y-2z=c , has: (a)no solution if a+b+c!=0 (b)unique solution if a+b+c=0 (c)infinite number of solutions if a+b+c=0 (d)none of these

The system of equations -2x+y+z=a , x-2y+z=b , x+y-2z=c , has: (a)no solution if a+b+c!=0 (b)unique solution if a+b+c=0 (c)infinite number of solutions if a+b+c=0 (d)none of these

The system of equations -2x+y+z=a , x-2y+z=b , x+y-2z=c , has: (a)no solution if a+b+c!=0 (b)unique solution if a+b+c=0 (c)infinite number of solutions if a+b+c=0 (d)none of these

The system of equations : ax-y-z=alpha-1 x-ay-z=alpha-1 x-y-alphaz=alpha-1 has no solution if alpha is :

Comprehension 2 Consider the system of linear equations alphax+y+z=m x+alphay+z=n x+y+alphaz=p If alpha=1\ &\ m!=p then the system of linear equations has- a. no solution b. \ infinite solutions c. unique solution d. \ unique solution if\ p=n

Comprehension 2 Consider the system of linear equations alphax+y+z=m x+alphay+z=n x+y+alphaz=p If alpha=1\ &\ m!=p then the system of linear equations has- a. no solution b. \ infinite solutions c. unique solution d. \ unique solution if\ p=n

Comprehension 2 Consider the system of linear equations alphax+y+z=m x+alphay+z=n x+y+alphaz=p If alpha=1\ &\ m!=p then the system of linear equations has- a. no solution b. \ infinite solutions c. unique solution d. \ unique solution if\ p=n

Consider the system of equations alphax+y+z = p, x+alphay+z=q and x+y+alphaz=r , then the sum of all possible distinct value(s) of alpha for which system does not possess a unique solution is