If `"Delta"_1=|x bb a x b a a x|a n d"Delta"_2=|x b a x|` are the given determinants, then `"Delta"_1=3("Delta"_2)^2` b.`d/(dx)("Delta"_1)=3"Delta"_2` c. `d/(dx)("Delta"_1)=3("Delta"_2)^2` d. `"Delta"_1=3"Delta"2 3//2`

If Delta_1=|[x, b, b],[ a, x, b],[ a, a, x]| a n d Delta_2=|[x, b],[ a, x]| are the given determinants, then Delta_1=3(Delta_2)^2 b. d/(dx)(Delta_1)=3Delta_2 c. d/(dx)(Delta_1)=3(Delta_2)^2 d. Delta_1=3(Delta_2)^ (3//2)

If Delta_(1)=|(x,b,b),(a,x,b),(a,a,x)|andDelta_(2)=|(x,b),(a,x)| are the given determinants, then a) Delta_(1)=3(Delta_(2))^(2) b) (d)/(dx)(Delta_(1))=3Delta_(2) c) (d)/(dx)(Delta_(1))=3(Delta_(2))^(2) d) Delta_(1)=3Delta_(2)^(3//2)

Delta_1 = |[x,b,b], [a,x, b] ,[a, a, x]| and Delta_2 = |[x,b],[a,x]| show that d(Delta_1)/ dx = 3 Delta_2

and "Delta"_2=x y^2z^3x^4y^5z^6x^7y^8z^9 Then "Delta"_1"Delta"_2 is equal to "Delta"2 3 b. "Delta"2 2 c. "Delta"2 4 d. none of these

Let delta=|A x x^2 1 B y y^2 1 C z z^2 1|a n d_1=|A B C x y z y z z xx y|, then show that delta = delta1

In a triangle A B C ,(r_1+r_2)/(1+cosC) is equal to (2a b)/(c"Delta") (b) ((a+b))/(c"Delta") (a b c)/(2"Delta") (d) (a b c)/("Delta"^2)

In a triangle A B C ,(r_1+r_2)/(1+cosC) is equal to (2a b)/(c"Delta") (b) ((a+b))/(c"Delta") (a b c)/(2"Delta") (d) (a b c)/("Delta"^2)

If Delta=|(1,2,3),(2,3,5),(3,6,12)|andDelta'=|(4,8,15),(3,6,12),(2,3,5)| , then a) Delta'=2Delta b) Delta'=-2Delta c) Delta'=Delta d) Delta'=-Delta

If p_1,\ p_2,\ p_3 are the altitudes of a triangle from its vertices A ,\ B ,\ C and "Delta" , the area of the triangle A B C , then 1/(p_1)+1/(p_2)-1/(p_3) is equal to s/"Delta" (b) (s-c)/"Delta" (c) (s-b)/"Delta" (d) (s-a)/"Delta"