Simplify `[(3sin2alpha)/(5+3cos2alpha)]+tan^(-1)[(tanalpha)/4],w h e r e-pi/2

Simplify [(3sin2 alpha)/(5+3cos2 alpha)]+tan^(-1)[(tan alpha)/(4)], where -(pi)/(2)

Simplify [(3 sin 2 alpha)/(5 + 3 cos 2 alpha)] + tan^(-1) [(tan alpha)/(4)], " where " -(pi)/(2) lt alpha lt (pi)/(2)

Simplify tan^-1[(3 sin 2alpha)/(5+3 cos2 alpha)]+tan^(-1)[(tan alpha)/4]

Simplify tan^(-1) [(3 sin 2 alpha)/(5 + 3 cos 2 alpha)] + tan^(-1) [(tan alpha)/(4)], " where " -(pi)/(2) lt alpha lt (pi)/(2)

Simplifytan^(-1) [(3 sin 2 alpha)/(5 + 3 cos 2 alpha)] + tan^(-1) [(tan alpha)/(4)], " where " -(pi)/(2) lt alpha lt (pi)/(2)

Evaluate tan^(-1)((3sin 2alpha)/(5+3cos2alpha)) +tan^(-1)((1)/(4)tan alpha) , where, -(pi)/(2) lt alpha lt (pi)/(2) .

If -pi/2 lt alpha lt pi/2 , then prove that tan^(-1)((3sin2alpha)/(5+3cos2alpha))+tan^(-1)((tanalpha)/4)=

If -(pi)/2 lt alpha lt (pi)/2 then prove that tan^(-1)((3sin 2 alpha)/(5+3 cos alpha))+tan^(-1)((tan alpha)/4)=

The expression (1 + sin 2 alpha )/( cos (2 alpha - 2pi) tan (alpha - (3pi)/(4 ))) -1/4 sin 2 alpha [ cot "" (alpha )/(2) + (alpha )/(2))] when simplified reduces to

The expression (sin alpha+cos alpha)/(cos alpha-sin alpha) tan((pi)/(4)+alpha)+1, alpha in (-(pi)/(4), (pi)/(4)) simplifies to :