If `(2^n+1)theta=pi` then `2^n costheta cos2theta cos2^2 theta .......cos 2^(n-1) theta=`

If (2^(n)+1)theta=pi then 2^(n)cos theta cos2 theta cos2^(2)theta......cos2^(n-1)theta=

If theta=pi/(2^n+1) then cos theta cos 2 theta cos 2^(2) theta...... Cos2^(n-1) theta is equal to

If theta=pi/(2^n+1) , prove that: 2^ncosthetacos2thetacos2^2theta....... cos2^(n-1)theta=1.

costheta+cos2theta+cos3theta+.......+cos(n-1)theta+cosntheta=

If theta=pi/(2^n+1) then costhetacos2thetacos2^2theta....cos2^(n-1)theta is equal to

If theta =(pi)/(2 ^(n) +1), then cos theta cos 2 theta cos 2^(2) theta …cos 2 ^(n-1)theta is equal to

If theta =(pi)/(2 ^(n) +1), then cos theta cos 2 theta cos 2^(2) theta …cos 2 ^(n-1)theta is equal to ................... A) (1)/(2 ^(n)) B) cos theta C) 2 D) 2^(n)

For all n in N, cos theta cos 2theta cos 4theta ....cos2^(n-1)theta equals to

For all n in N, cos theta cos 2theta cos 4theta ....cos2^(n-1)theta equals to