` 5^2 5^4 5^6...................5^(2x)=(0.04)^-28` ,

Lt_(x to2)(5^(-x)-0.04)/(x-2)=

lim_(x rarr2)(5^(-x)-(0.04))/(x-2)

(0.5x-4)/(2.4x+6)=-(5)/(3)

2x+3y=5 4x-5y=6

If the circumference of the circle x^2+y^2+8x+8y-b=0 is bisected by the circle x^2+y^2=4 and the line 2x+y=1 and having minimum possible radius is 5x^2+5y^2+18 x+6y-5=0 5x^2+5y^2+9x+8y-15=0 5x^2+5y^2+4x+9y-5=0 5x^2+5y^2-4x-2y-18=0

(4/5)^3xx(4/5)^-6=(4/5)^(2x-1) ,x=___

Solve each of the following equation. Also, verify the result in each case. 1. ((5x-1))/3-((2x-2))/3=1 2. 0. 6 x+4/5=0. 28 x+1. 16 3. 0. 5 x+x/3=0. 25 x+7

(1+2(x+4)^(- 0. 5))/(2-(x+4)^(0. 5))+5(x+4)^(0. 5) Find the domain of the following function

ln Delta ABC cosA= -(2)/(3) the equation with roots sin A ,tan A is 1) 6x^(2)+sqrt(5)x-5=0 2) 6x^(2)-sqrt(5)x+5=0 3) 6x^(2)-sqrt(5)x-5=0 4) 6x^(2)+sqrt(5)x+5=0