In tringle ABC , `(a^2-b^2-c^2)tanA+(a^2-b^2+c^2)tanB=`

In a triangle A B C ,\ (a^2-b^2-c^2)tanA+(a^2-b^2+c^2)tanB is equal to (a^2+b^2-c^2)tanC (b) (a^2+b^2+c^2)tanC (b^2+c^2-a^2)tanC (d) none of these

In a triangle A B C ,\ (a^2-b^2-c^2)tanA+(a^2-b^2+c^2)tanB is equal to (a^2+b^2-c^2)tanC (b) (a^2+b^2+c^2)tanC (b^2+c^2-a^2)tanC (d) none of these

In tringle ABC (a^(2)-b^(2)-c^(2))tan A+(a^(2)-b^(2)+c^(2))tan B=

In triangleABC , (b^(2)+c^(2)-a^(2))tanA=

With usual notation show that (c^2-a^2+b^2)tanA = (a^2-b^2+c^2)tanB = (b^2-c^2+a^2)tanC

In triangleABC , (c^(2)+a^(2)-b^(2))tanB=

In a DeltaA B C , prove the following : (c^2-a^2+b^2)tanA=(a^2-b^2+c^2)tanB=(b^2-c^2+a^2)tanC

In Delta ABC prove that ( a^2 -b^2 + c^2) tanB = (a^2 + b^2 - c^2) tanC

In any triangle ABC , (tanA/2-tanB/2)/(tanA/2+tanB/2) is equal to