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The number of atoms of 0.03 g of alumini...

The number of atoms of 0.03 g of aluminium is nearly (Al = 27)

A

`6.68 xx10^(20)`

B

`6.68xx10^(21)`

C

`6.68 xx10^(22)`

D

`6.68xx10^(23)`

Text Solution

Verified by Experts

The correct Answer is:
A
The number of atoms in 0.3 g of Al
`=(6.02xx10^(23))/(27) xx0.03`
`= 0.668xx10^(21) = 6.68xx10^(20)`
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