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Suppose the chemists had selected 10^20 ...

Suppose the chemists had selected `10^20` as the number of particles in a mole. The molar mass of oxygen gas would be
(Use Avogadro number = `6.0 xx 10^23)`

A

`5.33xx10^(-3)g`

B

`5.35xx10^(-23)g`

C

`5.33xx10^(-43)g`

D

`32xx10^(3)g`

Text Solution

Verified by Experts

The correct Answer is:
A
`6xx10^(23)` molecules of oxygen weighs 32 g
1 molecule of oxygen weighs `(32)/(6xx10^(23))`
`10^(20)` molecules of oxygen weighs
`(32xx10^(20))/(6xx10^(23))=5.33xx10^(-3) g`
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Suppose the chemists had chosen 10^20 as the number of particles in a mole. What would be the molecular mass of oxygen gas ?

A mole is a collection of 6.022 xx 10^23 particles and the number 6.022 xx 10^23 is called Avogadro number. The mass of this number of atoms in an element is equal to its gram atomic mass and mass of this number of molecules in a compound is equal to its gram molecular mass. The volume occupied by this number of molecules of a gas at N.T.P is 22.4 L. When 6.022 xx 10^23 molecules of a substance are dissolved in 1L of solution, the solution is known as 1 molar volume. Suppose the chemists would have choosen 10^20 as the number of particles in a mole, the mass of 1 mole of oxygen gas would be:

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Equals number of atoms are contained in one gram atomic weight of each element and the same number of molecules are found in one gram molecules weight of any compound . The terms gram atomic weight and gram molecular weight are used to refer to a fixed numer(Avogadro's number 6.022xx10^(23)) of particle. the term 'mole' stands for the amount of material which contains these number of particles. Compute gram molecular weight of H_(2) gas if 4 g of H_(2) gas contains 24.09 xx 10^(23) atoms.

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