How many molecules of sulphur are present in 9.6 g of sulphur ( atomic mass of S = 32) ?

Options

A. `2.25xx10^(22)`
B. `2.408xx10^(23)`
C. `6.02 xx10^(23)`
D. `18.06 xx10^(22)`

Answer

A

Explanation

Number of atoms of sulphur in 9.6 g
`=(6.02xx10^(23)xx9.6)/(32) = 18.06 xx10^(22)`
One molecule of sulphur contains 8 atoms
Number of molecules of sulphur in 9.6 g
`=(18.06xx10^(22))/(8) = 2.25xx10^(22)`