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A sample of CaCO3 has Ca = 40%, C = 12% ...

A sample of `CaCO_3` has `C_a = 40%,` `C = 12%` and `O = 48%`. If the law of constant proportion is true then the weight of calcium in 5 g of a sample of `CaCO_3` from another source will be

A

0.20 g

B

2.0 g

C

2.5 g

D

4.0 g

Text Solution

Verified by Experts

The correct Answer is:
B
According to law of constant proportion, `40%` Ca means 100 g of sample of `CaCO_3` contains 40 g of Ca. Hence 5 g of the sample of `CaCO_3` contains `(5xx40)/(100)=2g.`
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