The ratio of mass of 1 mole of sulphur and `10^(23)` atoms of sulphur is ______ . ( S = 32)

Options

A. `(32)/(6.023)`
B. `32xx6.023`
C. 6.023
D. 32

Answer

C

Explanation

Mass of 1 mole of sulphur = 32 gm
Mass of `10^(23)` atoms of sulphur
`=(32)/(6.023xx10^(23))xx10^(23) gm=(32)/(6.023)`
The ratio :
`("Mass of " 1 "mole" " of sulphur")/("Mass of " 10^(23)"atoms of sulphur")=(32)/(32/(6.023))`
`" "= 6.023`