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A sample of CaCO3 has Ca = 40%, C = 12% ...

A sample of `CaCO_3` has `C_a = 40%,` `C = 12%` and `O = 48%`. If the law of constant proportion is true then the weight of calcium in 5 g of a sample of `CaCO_3` from another source will be

A

0.2 g

B

0.4 g

C

2 g

D

4 g

Text Solution

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The correct Answer is:
C
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