If W is the amount of adsorbate adsorbed by unit mass of an adsorbent whose mass is x g and the initial pressure and eqilibrium pressure of the adsorbate are `p_(1) and P_(2)` respectively, Freundlich's adsorption isotherm can be written as

Options

A. `w//s=KP_(1)""^(1//n)`
B. `w//x=KP_(2)""^(1//n)`
C. `W=PK_(1)""^(1//n)`
D. `W=KP_(2)""^(1//n)`

Answer

D

Explanation

`W/X = KP _(2) ""^(1//n) - "as "x = 1 "g "thereforeW=KP_(2)""^(1//n)`