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In Carius method, 0.099 g organic compo...

In Carius method, `0.099 g ` organic compound gave `0.287 g AgCl.` The percentage of chlorine in the compound will be

A

28.6

B

71.7

C

35.4

D

64.2

Text Solution

Verified by Experts

The correct Answer is:
B
`0.287 " g of AgCl "-= (0.287 xx 35.5)/(143.5) =0.071 g of Cl_2`
`therefore % of " Chlorine" = (0.071)/(0.099)xx100 =71.7`
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