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Empirical formula of an organic compound...

Empirical formula of an organic compound having molecular weight 60 is `CH_(2)O`. What is its molecular formula?

A

`C_6H_(12)O_(6)`

B

`C_4H_8O_4`

C

`C_3H_6O_3`

D

`C_2H_4O_2`

Text Solution

Verified by Experts

The correct Answer is:
D
`("Molar mass")/("Emp. Formula mass ")=("Molecalar formula ")/("Emp. Formula")`
`therefore " Molecular formula"= 60/30 [CH_2O]=C_2H_4O_2`
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