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0.1 g of an organic compound gave 0.222g...

0.1 g of an organic compound gave 0.222g of `Mg_(2)P_(2)O_(7)`. What is the percentage of phosphorus in the compound ?

A

0.32

B

0.42

C

0.52

D

0.62

Text Solution

Verified by Experts

The correct Answer is:
D
Amount of `P=(0.222 xx 62)/(222) = 0.062 g `
`therefore " % of " P= (0.062)/(0.1) xx 100 =62.`
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