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In the estimation of nitrogen by Duma's ...

In the estimation of nitrogen by Duma's method 1.18 g of an organic compound gave 224 ml of `N_(2)` at NTP. The percentage of nitrogen in the compound is about

A

`20.0`

B

11.8

C

47.5

D

23.7

Text Solution

Verified by Experts

The correct Answer is:
D
Amount of `C=(0.147 xx 12)/(44) =0.4 g:`
Amount of `H_2 =(0.12 xx 2)/(18)=0.013 g`
`therefore "% of C"=(0.04)/(0.2)xx 100=20`
`"% of H_2 =6.66`
`therefore "% of "O_2=73.29`
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