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A rod 0.5 m long has two masses each of ...

A rod 0.5 m long has two masses each of 20 gram stuck at its ends. If the masses are treated as point masses and if the mass of the rod is neglected, then the moment of inertia of the system about a transverse axis passing through the centre is

A

`1.25xx10^(-3)kg-m^(2)`

B

`2.5xx10^(-3)kg-m^(2)`

C

`4xxxx10^(-3)kg-m^(2)`

D

`5xx10^(-3)kg-m^(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
`I=Sigmamr^(2)=2m_(1)r_(1)^(2)=2[20xx10^(-3)xx0.25xx0.25]`
`=2.5xx10^(-3)" kg-m"^(2)`
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