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The ratio of the dimension of Planck's c...

The ratio of the dimension of Planck's constant and that of moment of inertia is the dimension of

A

frequency

B

angular momentum

C

velocity

D

time

Text Solution

Verified by Experts

The correct Answer is:
A

`E=hv" "therefore h=(E)/(v)=ET`
`therefore [h]=[M^(1)L^(2)T^(-2)T^(1)]=[M^(1)L^(2)T^(-1)]`
Rotational Motion
(ii) `I=Sigma mr^(2)" "therefore" "[I]=[M^(1)L^(2)T^(0)]`
`therefore" "[(h)/(I)]=[(M^(1)L^(2)T^(-1))/(M^(1)L^(2)T^(0))]=[T^(-1)]=[(1)/(T)]`
But `(1)/(T)=` Frequency (v)
`therefore" "(h)/(I)` has the dimensions of frequency.
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