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A torque of magnitude 500 Nm acts on a b...

A torque of magnitude 500 Nm acts on a body of mass 16 kg and produces and angular acceleration of `"20 rad/s"^(2)`. The radius of gyration of the body is

A

`(5)/(4)m`

B

`(4)/(5)m`

C

`(2)/(3)m`

D

`(3)/(2)m`

Text Solution

Verified by Experts

The correct Answer is:
A
`tau=Ialpha" "therefore" "I=(tau)/(alpha)=(500)/(20)="25 kg-m"^(2)`
`I=MK^(2)" "therefore" "(25)/(16)=K^(2)" "therefore " "K=(5)/(4)m`
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