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A constant torque of 31.4 Nm is applied ...

A constant torque of 31.4 Nm is applied to a pivoted wheel. If the angular acceleration of the wheel is `2pi" rad/s"^(2)`, then its moment of inertia is

A

`"5 kg m"^(2)`

B

`"2.5 kg m"^(2)`

C

`"10 kg m"^(2)`

D

`"1.25 kg m"^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`I=(tau)/(alpha)=(31.4)/(2xx3.14)=5`
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