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A wheel has a moment of inertia of 5xx10...

A wheel has a moment of inertia of `5xx10^(-3) kg m"^(2)` and is making `"20 rev/s".` What is the magnitude of the torque required to stop it in 10 s?

A

`1.5pixx10^(-2)N.m`

B

`2pixx10^(-2)N-m`

C

`3pixx10^(-2)N-m`

D

`3.5pixx10^(-2)N-m`

Text Solution

Verified by Experts

The correct Answer is:
B
`tau=Ialpha=(I(omega_(2)-omega_(1)))/(t)=(I(2pin_(2)-2pin_(1)))/(t)`
`=5xx10^(-3)[(0-2pixx20)/(10)]`
`therefore" Magnitude of torque"=2pixx10^(-2)"N-m"`
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