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A torque of 100 N-m acting on a wheel at...

A torque of 100 N-m acting on a wheel at rest, rotates it through 200 radian in 10 s. What is the moment of inertia of the wheel?

A

`"10 kg-m"^(2)`

B

`"15 kg-m"^(2)`

C

`"20 kg-m"^(2)`

D

`"25 kg-m"^(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
`theta=0+(1)/(2)alphat^(2)" "therefore 200=(1)/(2)xx alphaxx100`
`therefore" "alpha="4 rad/s"^(3)`
`"and I"=(tau)/(alpha)=(100)/(4)="25 kg-m"^(2)`
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