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A toraue of magnitude 4000 N-m, acts on ...

A toraue of magnitude 4000 N-m, acts on a body of mass 2 kg. If the angular acceleration produced in the body is `"20 rad/s"^(2)`, then the radius of gyration of the body is

A

5 m

B

10 m

C

15 m

D

20 m

Text Solution

Verified by Experts

The correct Answer is:
B
`tau=Ialpha" but "I=MK^(2)" "therefore tau=MK^(2)alpha`
`therefore" "K^(2)=(tau)/(M alpha)=(4000)/(20xx20)=100`
`therefore" "K = 10m`
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