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O is the centre of an equilateral triang...

`O` is the centre of an equilateral triangle `ABC`. `F_(1), F_(2)` and `F_(3)` are the three forces acting along the sides `AB, BC` and `AC` respectively. What should be the value of `F_(3)` so that the total torque about `O` is zero?

A

`(F_(1)-F_(2))`

B

`(F_(1)+F_(2))`

C

`2(F_(1)+F_(2))`

D

`((F_(1)+F_(2)))/(2)`

Text Solution

Verified by Experts

The correct Answer is:
B


Let d, d and d be the perpendicular distances of `F_(1), F_(2) and F_(3)` from the centre O of the equilaterial triangle. Torques of `F_(1) and F_(2)` about O are anticlockwise while the torque of `F_(3)` about O is clockwise. As per given condition,
`F_(1)xx d+F_(2)xx d-F_(3)xxd=0`
`therefore F_(1)+F_(2)=F_(3) or F_(3)=F_(1)+F_(2)`
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