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A costant torque of 400 N turns a flywhe...

A costant torque of 400 N turns a flywheel at rest and of `"M.I. 100 kgm"^(2)` about an axis through its centre. What is the change in its angular velocity in 4 s?

A

8 rad/s

B

12 rad/s

C

16 rad/s

D

20 rad/s

Text Solution

Verified by Experts

The correct Answer is:
C
`alpha=(tau)/(I)=(400)/(100)="4 rad/s"^(2)`
Let `omega` be the angular velocity after 4 s
then `omega=omega_(0)+alphat=0+4xx4="16 rad/s"`
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