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A rope is wound round a hollow cylinder ...

A rope is wound round a hollow cylinder of mass M and radius R. If the rope is pulled with a force F newton, then the angular acceleration of the cylinder will be

A

`MRF`

B

`(MR)/(F)`

C

`(R)/(MF)`

D

`(F)/(MR)`

Text Solution

Verified by Experts

The correct Answer is:
D
The M.I. of the hollow cylinder about its axis is `I=MR^(2)`
The torque acting on the cylinder `vec(tau)=vecFxxvecR` ltbr. But `tau=Ialpha`
`therefore" Angular acceleration "(alpha)=(tau)/(I)=(FxxR)/(MR^(2))=(F)/(MR)`
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Knowledge Check

  • A rope is wound round a hollow cylinder of mass 2 kg and radius 0.5 m. If the rope is pulled with a force of 80 N, the angular acceleration of the cylinder will be -

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