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A rod of length 2 m, has a mass of 0.12 ...

A rod of length 2 m, has a mass of 0.12 kg. Its moment of inertia about an axis passing through its one end and perpendicular to the length of the rod is

A

`"0.16 kg - m"^(2)`

B

`"0.12 kg - m"^(2)`

C

`"0.32 kg - m"^(2)`

D

`"0.08 kg - m"^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`I=(ml^(2))/(3)=(0.12xx4)/(3)="0.16 kg - m"^(2)`
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