Home
Class 12
PHYSICS
A uniform disc of mass 5 kg has a radius...

A uniform disc of mass 5 kg has a radius of 0.5 m. Its moment of inertia about an axis passing through a point on its circumference and perpendicular to its plane is

A

`"1.25 kg - m"^(2)`

B

`"0.5 kg - m"^(2)`

C

`"4 kg - m"^(2)`

D

`"1.875 kg - m"^(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
`I_(o)=I_(c)+Mh^(2)=(MR^(2))/(2)+MR^(2)`
`therefore I_(o)=(3)/(2)MR^(2)=(3)/(2)xx5xx25xx10^(-2)`
`="1.875 kg - m"^(2)`
Promotional Banner

Topper's Solved these Questions

  • ROTATIONAL MOTION

    MARVEL PUBLICATION|Exercise TEST YOUR GRASP - 3|8 Videos

  • OSCILLATIONS

    MARVEL PUBLICATION|Exercise MCQ|368 Videos

  • SEMICONDUCTORS

    MARVEL PUBLICATION|Exercise MCQs|261 Videos

Similar Questions

Explore conceptually related problems

A thin ring has mass 0.25 kg and radius 0.5 m. Its moment of inertia about an axis passing through its centre and perpendicular to its plane is ………… .

A disc of mass m and radius R has a concentric hole of radius r . Its moment of inertia about an axis through its center and perpendicular to its plane is

The diameter of a thin circular disc of mass 2 kg is 0.2 m. Its moment of inertia about an axis passing through the edge and perpendicular to the plane of the disc is

A solid cylinder has mass M radius R and length / its moment of inertia about an axis passing through its centre and perpendicular to its own axis is

The moment of inertia of a uniform circular disc about a tangent in its own plane is 5/4MR^2 , where M is mass and R is the radius of the disc. Find its moment of inertia about an axis through its centre and perpendicular to its plane.

The moment of inertia of a copper disc, rotating about an axis passing through its centre and perpendicular to its plane