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The M.I. of a ring about an axis passing...

The M.I. of a ring about an axis passing through its centre and perpendicular to its plane is `"2 kg - m"^(2)`, then its M.I. about any diameter is

A

`"3 kg - m"^(2)`

B

`"1 kg - m"^(2)`

C

`"4 kg - m"^(2)`

D

`"2 kg - m"^(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
`I_(1)=MR^(2), I_(2)=(MR^(2))/(2)" "therefore I_(2)="1kg - m"^(2)`
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