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A wire of mass m and length l is bent in...

A wire of mass `m` and length `l` is bent in the form of circular ring. The moment of inertia of the ring about its axis is

A

`4pi^(2)ML^(2)`

B

`(ML^(2))/(8pi^(2))`

C

`8pi^(2)ML^(2)`

D

`(ML^(2))/(4pi^(2))`

Text Solution

Verified by Experts

The correct Answer is:
D
`2pir=L" "therefore r=(L)/(2pi)" "therefore" M.I "=Mr^(2)=(ML^(2))/(4pi^(2))`
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