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Moment of inertia of a rod of mass M and...

Moment of inertia of a rod of mass M and length L about an axis passing through a point midway between centre and end is

A

`(7ML^(2))/(12)`

B

`(ML^(2))/(44)`

C

`(7ML^(2))/(48)`

D

`(7ML^(2))/(44)`

Text Solution

Verified by Experts

The correct Answer is:
C

By parallel axes theorem
`I-(ML^(2))/(12)+M[(L)/(4)]^(2)=(ML^(2))/(12)+(ML^(2))/(16)=(7ML^(2))/(48)`
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