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A body of mass 2 kg is rotating on a cir...

A body of mass 2 kg is rotating on a circular path of radius 0.5 m, with an angular velocity of 20 rad/s. If the radius of the path is doubled, then the new angular velocity will be

A

5 rad/sec

B

2.5 rad/sec

C

10 rad/sec

D

8 rad/sec

Text Solution

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The correct Answer is:
To solve the problem, we will use the principle of conservation of angular momentum. The angular momentum of a rotating body is given by the formula: \[ L = I \omega \] where \(L\) is the angular momentum, \(I\) is the moment of inertia, and \(\omega\) is the angular velocity. ### Step-by-Step Solution: 1. **Identify the initial conditions**: - Mass of the body, \(m = 2 \, \text{kg}\) - Initial radius, \(r_1 = 0.5 \, \text{m}\) - Initial angular velocity, \(\omega_1 = 20 \, \text{rad/s}\) 2. **Calculate the initial moment of inertia**: For a point mass rotating in a circular path, the moment of inertia \(I\) is given by: \[ I_1 = m r_1^2 \] Substituting the values: \[ I_1 = 2 \, \text{kg} \times (0.5 \, \text{m})^2 = 2 \times 0.25 = 0.5 \, \text{kg m}^2 \] 3. **Calculate the initial angular momentum**: Using the formula for angular momentum: \[ L_1 = I_1 \omega_1 = 0.5 \, \text{kg m}^2 \times 20 \, \text{rad/s} = 10 \, \text{kg m}^2/\text{s} \] 4. **Identify the new conditions**: - New radius, \(r_2 = 2r_1 = 2 \times 0.5 \, \text{m} = 1.0 \, \text{m}\) 5. **Calculate the new moment of inertia**: \[ I_2 = m r_2^2 = 2 \, \text{kg} \times (1.0 \, \text{m})^2 = 2 \times 1 = 2 \, \text{kg m}^2 \] 6. **Apply conservation of angular momentum**: Since there is no external torque acting on the system, the angular momentum before and after must be equal: \[ L_1 = L_2 \] Therefore: \[ I_1 \omega_1 = I_2 \omega_2 \] Substituting the known values: \[ 10 \, \text{kg m}^2/\text{s} = 2 \, \text{kg m}^2 \times \omega_2 \] 7. **Solve for the new angular velocity \(\omega_2\)**: \[ \omega_2 = \frac{10 \, \text{kg m}^2/\text{s}}{2 \, \text{kg m}^2} = 5 \, \text{rad/s} \] ### Final Answer: The new angular velocity \(\omega_2\) when the radius is doubled is \(5 \, \text{rad/s}\). ---

To solve the problem, we will use the principle of conservation of angular momentum. The angular momentum of a rotating body is given by the formula: \[ L = I \omega \] where \(L\) is the angular momentum, \(I\) is the moment of inertia, and \(\omega\) is the angular velocity. ...
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