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A body of mass m and radius of gyration ...

A body of mass m and radius of gyration K has an angular momentum L. Then its angular velocity is

A

`(mK^(2))/(L)`

B

`(L)/(mK^(2))`

C

`mK^(2)K`

D

`(K^(2))/(mL)`

Text Solution

Verified by Experts

The correct Answer is:
B

`L=Iomega=mK^(2)omega" "therefore" "omega=(L)/(mK^(2))`
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