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A solid cylinder of moment of inertia 0....

A solid cylinder of moment of inertia `0.625 kgm^(2)` , rotates about its axis with an angular speed of 200 rad/s. What is the magnitude of angular momentum of the cylinder about its axis ?

A

`"25 kg m"^(2)//s`

B

`"12.5 kg m"^(2)//s`

C

`"62.5 kg m"^(2)//s`

D

`"125 kg m"^(2)//s`

Text Solution

Verified by Experts

The correct Answer is:
D
Angular momentum `L=Iomega`
`therefore L=0.625xx200="125 kg m"^(2)//s`
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