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A uniform metre scale of mass 0.2 kg is ...

A uniform metre scale of mass 0.2 kg is rotated about an axis passing through its one end and perpendicular to its length at the rate of 60 revolutions/minute. What is its angular momentum?

A

`(2pi)/(15)" kg m"^(2)//s`

B

`(4pi)/(15)" kg m"^(2)//s`

C

`(pi)/(15)" kg m"^(2)//s`

D

`"1 kg m"^(2)//s`

Text Solution

Verified by Experts

The correct Answer is:
A
For the metre scale,
`I=(mL^(2))/(3)=(0.2xx1^(2))/(3)=(1)/(15)" kgm"^(2)`
and `omega=2pin=2pixx1=2pi" rad/s"`
`therefore" Angular momentum "`
`=Iomega=(1)/(15)xx2pi=(pi)/(15)km^(2)//s`
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