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An electron revolves around the nucleus ...

An electron revolves around the nucleus of an atom in a circular orbit of radius 4 Å with a speed of `5xx 10^(6)m//s`. What is the angular momentum of the electron ? [`m_(e) = 9 xx 10^(-31) kg`].

A

`2xx10^(-33)" kg m"^(2)//s`

B

`1.8xx10^(-33)" kg m"^(2)//s`

C

`3xx10^(-32)" kg m"^(2)//s`

D

`0.8xx10^(-34)" kg m"^(2)//s`

Text Solution

Verified by Experts

The correct Answer is:
B
Angular momentum of the electron (L) = mvr
`therefore L=9xx10^(-31)xx5xx10^(6)xx4xx10^(-10)`
`=1.8xx10^(-33)" kgm"^(2)//s`
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